Posted by Chris on Monday, October 29, 2012 at 2:23am.
Actually, the mass of Fe in the residue is 2.407-Al2O3. The Fe2O3 has all lost its oxygen, leaving only Fe.
So, if you started out with x moles of Fe2O3 and y grams of Al2O3, then converting the Fe2O3 to grams,
159.69x + y = 3.064
55.85(2x) + y = 2.407
The equations may look a bit funny, but we really don't have to convert the moles of Al2O3 to grams, since the mass doesn't change. And, of course the (2x) appears because each mole of Fe2O3 has 2 Fe atoms in it.
Solving the equations yields
x = 0.01369 moles Fe2O3
y = 0.8778 grams of Al2O3
Now we need to convert the moles back to grams: .01369 moles = 2.1862 grams Fe2O3
2.1862/3.064 = 71.35%
Actually, we really didn't have to convert the moles back to grams, since we had the mass of Al2O3 already. Just subtract its fraction from 100%.
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