Tuesday

January 27, 2015

January 27, 2015

Posted by **Anonymous** on Sunday, October 28, 2012 at 10:42pm.

- annual interest -
**MathMate**, Sunday, October 28, 2012 at 10:48pm12000*0.05=600

12000*0.07=840

Proportion at 5% = (840-760)/(840-600)=1/3

Proportion at 7% = (760-600)/(840-600)= 2/3 (or 1-1/3=2/3)

(1/3) of 12000 = 4000 at 5%

(2/3) of 12000 = 8000 at 7%

- annual interest -
**Reiny**, Monday, October 29, 2012 at 8:39amor

amount invested at 5% --- x

amount invested at 7% --- 1200-x

.05x + .07(12000-x) = 760

5x + 7(12000-x) = 76000

-2x = -8000

x = 4000 at 5% , then 12000-4000 or 8000 at 7%

**Answer this Question**

**Related Questions**

math - you invested $4000 in two accounts paying 2% and 9% annual interest, ...

Math - You invested $14,000 in two accounts paying 5% and 9% annual interest, ...

math - An investment adviser invested $14,000 in two accounts. One investment ...

math - An investment adviser invested $14,000 in two accounts. One investment ...

math - An investment adviser invested $14,000 in two accounts. One investment ...

algebra - An investment adviser invested $14,000 in two accounts. One investment...

MATH - An investment adviser invested $14,000 in two accounts. One investment ...

Algebra - An investment adviser invested $14,000 in two accounts. One investment...

-Math-Desperate - An investment adviser invested $14,000 in two accounts. One ...

Math - An investment adviser invested $14,000 in two accounts. One investment ...