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November 25, 2014

November 25, 2014

Posted by **Vevea Tepou** on Sunday, October 28, 2012 at 10:04pm.

- Discrete Mathematics -
**MathMate**, Sunday, October 28, 2012 at 10:08pmThink of the case of 4 people for 3 different posts, and if any one person can hold zero, one, two or three posts.

There are 4 choices for the president, 4 choices for the secretary, and 4 choices for the treasurer. Invoking the multiplication rule, there is a total of 4×4×4=64 possible ways to choose the three posts.

Can you now extend the situation to 20 people?

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