What element forms an ion with an electronic configuration of [Xe] and a –2 charge?
Would that be Te^2-?
I need help asap!
Thanks it was correct!
To find the element that forms an ion with an electronic configuration of [Xe] and a -2 charge, we need to consider the position of the element in the periodic table.
1. Look up the atomic number of xenon (Xe) in the periodic table. It is 54.
2. To determine the electron configuration of the neutral xenon atom, we write it by filling up the electron orbitals based on the Aufbau principle. The electronic configuration of xenon is [Kr]5s^24d^105p^6.
3. To form an ion with a -2 charge, xenon needs to gain two electrons. Entering this value into the electron configuration, we get [Kr]5s^24d^105p^6 + 2e^-.
4. Since the valence shell of xenon is the 5p shell, we remove the two outermost electrons from the 5p^6 subshell. This gives us the electron configuration of [Kr]5s^24d^105p^4.
5. Now, we identify the element that has this electron configuration. Looking at the periodic table, we find that the element with an electron configuration of [Kr]5s^24d^105p^4 is iodine (I), which has an atomic number of 53.
Therefore, the element that forms an ion with an electronic configuration of [Xe] and a -2 charge is iodine (I).