Posted by alleyx3 on Sunday, October 28, 2012 at 7:32pm.
pH = pKa + log(base)/(acid)
You want 100 mL x 0.5M = 0.05 mols
6.5 = 6.64 + log (B/A)
Solve for B/A, then
A + B = 0.05.
Two equations and two unknowns, Solve for acid and base mols, then convert to grams from g = mols x molar mass.
I would check myself upon finishing each by substituting grams of each salt back into the HH equation and see if it givs the desired pH.
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