Wednesday

April 16, 2014

April 16, 2014

Posted by **Katelyn** on Sunday, October 28, 2012 at 7:31pm.

- Algebra -
**PsyDAG**, Monday, October 29, 2012 at 5:40pm3s + 4p = 123

3s + 2p = 85.5

Subtract second equation from the first.

2p = 37.5

p = 18.75

You should be able to work it from here.

- Algebra -
**Mr.Mathews**, Tuesday, January 14, 2014 at 6:41pm3 sweatshirts and 2 sweatpants for 85.50 --> 3x+2y=85.50

3 sweatshirts and 4 sweatpants for 123 --> 3x+4y=123

solve for one of the variables in either equation (in terms of the other variable) and insert the answer into the other equation to get an actual value of the other variable

3x+2y=85.5

3x=85.5-2y

x=(85.5-2y)/3

x=28.5-(2/3)y --> insert the "x" value into the other equation to solve for "y"

3(28.5-(2/3)y)+4y=123

85.5-2y+4y=123

2y=37.5

y=18.75 --> now insert the "y" value into the first equation to get an actual value for "x"

3x+2(18.75)=85.5

3x+37.5=85.5

3x=48

x=16

FINAL ANSWER:(x=16 and y=18.75)

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