Homework Help: Math

Posted by Michael on Sunday, October 28, 2012 at 4:22pm.

Assume that the average annual salary for a worker in the United States is $30,500 and that the annual salaries for Americans are normally distributed with a standard deviation equal to $6,250. Find the following:

(A) What percentage of Americans earn below $19,000?
(B) What percentage of Americans earn above $40,000?

Math - Michael, Sunday, October 28, 2012 at 4:46pm
This is what I am getting so maybe someone can tell me if I am right and if not where am I going wrong.

Z = (score-mean)/SD
A. Z(19,000)= (19,000-30,500)/6250= -1.84
P(x<19,000)=P(z< -1.84) = 23.40 23%

B. z(40,000) = (40,000-30,500)/6250= 1.52
P(x>40,000) = P (z> 1.52) = + 23.40 23%

Answer this Question

Related Questions

math - Assume that the average annual salary for a worker in the United States ...
precalc - Assume that this year, n = 1, the average annual salary for women in ...
math - Assume that the average annual salary for a worker in the United States ...
Statistics - Assume that the average annual salary for a worker in the United ...
Statistics - The average annual salary of employees at Wintertime Sports was $28...
algebra - mei salary starts at 16,000 per year with annual raises or 1,500. ...
MATH urgent!!! - My problem: From 1992 to 1996, the annual income for all the ...
TRIG - A WORKER PRESENT SALARY IS 24 PER ANNUM HIS ANUAL INCREMENT IS 10% OF HIS...
Math - Here is my problem: Annual Earnings. A recent survey reported the ...
Statistics - An economist found that a random sample of 42 high school teachers ...

For Further Reading

First Name:
School Subject:
Answer: