Posted by **Rob** on Sunday, October 28, 2012 at 2:48pm.

A bullet of mass m=0.060 kg hits a 5.0 kg block with an initial speed of 225 m/s. The block is connected to a spring that is attached to a wall. The friction between the block and the table is negligible. Upon impact, the bullet bounces back from the box with a speed of 75 m/s.

A) Calculate the speed of the block right after the collision.

I thought the equation to use was mv of bullet = (M+m)V of block. I came up with 2.67 but the answer is supposed to be 3.6 m/s.

B) As a result of the collision, the spring compresses to a mazimum of 0.20m. Find the spring constant

--The equation to this is 1/2mv^2 = 1/2kx^2 right? I can't get the answer to this question without the answer to part A.

C) Find the inelastic energy loss during the collision

## Answer this Question

## Related Questions

- Physics - A bullet of mass m=0.060 kg hits a 5.0 kg block with an initial speed ...
- Physics... Help! - A bullet of mass m=0.060 kg hits a 5.0 kg block with an ...
- Physics- Elena please help! - A 20.0 g bullet is fired horizontally into a 85 g ...
- Physics - You have been asked to design a "ballistic spring system" to measure ...
- Physics HELP! - A 20.0 g bullet is fired horizontally into a 85 g wooden block ...
- Physics - A bullet is fired into a block of wood with speed 250 m/s. The block ...
- Physics - A 2.50g bullet, traveling at a speed of 425m/s, strikes the wooden ...
- physics - A 20 g bullet moving horizontally with a speed v hits a 2-kg block of ...
- Physics - A 11.0-g bullet is fired horizontally into a 101-g wooden block that ...
- physics - A 10.0-g bullet is fired horizontally into a 101-g wooden block that ...