Thursday

November 20, 2014

November 20, 2014

Posted by **Rob** on Sunday, October 28, 2012 at 2:48pm.

A) Calculate the speed of the block right after the collision.

I thought the equation to use was mv of bullet = (M+m)V of block. I came up with 2.67 but the answer is supposed to be 3.6 m/s.

B) As a result of the collision, the spring compresses to a mazimum of 0.20m. Find the spring constant

--The equation to this is 1/2mv^2 = 1/2kx^2 right? I can't get the answer to this question without the answer to part A.

C) Find the inelastic energy loss during the collision

**Answer this Question**

**Related Questions**

Physics... Help! - A bullet of mass m=0.060 kg hits a 5.0 kg block with an ...

Physics - A bullet of mass m=0.060 kg hits a 5.0 kg block with an initial speed ...

Physics- Elena please help! - A 20.0 g bullet is fired horizontally into a 85 g ...

Physics HELP! - A 20.0 g bullet is fired horizontally into a 85 g wooden block ...

Physics - A 2.50g bullet, traveling at a speed of 425m/s, strikes the wooden ...

Physics - A bullet is fired into a block of wood with speed 250 m/s. The block ...

Physics - A 11.0-g bullet is fired horizontally into a 101-g wooden block that ...

physics - A 10.0-g bullet is fired horizontally into a 101-g wooden block that ...

physics - A bullet with mass 4.95 g is fired horizontally into a 1.994 kg block ...

Physics - A bullet with mass 4.91 g is fired horizontally into a 1.981-kg block...