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September 1, 2014

September 1, 2014

Posted by **agak** on Sunday, October 28, 2012 at 2:10pm.

A) What is the probability that exactly four of them will catch a cold?

B) What is the probability that three or more of them will catch a cold?

C) On average, how many of these five people would you expect to catch a cold?

- xiamen university -
**Reiny**, Sunday, October 28, 2012 at 5:32pmprob of cold = .62

prob of not cold = .38

a) prob of 4 of 5 catch cold

= C(5,4) (.62)^4 (.38)

b) prob 3 or more

= prob 3 + prob 4 + prob 5

= C(5,3)(.62)^3 (.38)^2 + C(5,4) (.62)^4 (.38) + C(5,5) .62^5

= ...

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