Math
posted by Rutba on .
a firecracker is fired from the ground. The height of the firecracker at a given time is modeled by the function h(t) =5t^2+50t, where h(t) is the height in metres and t is the time in seconds. When will the firecracker reach a height of 45m ?

solve for t in
45 = 5t^2 + 50t
5t^2  50t + 45 = 0
t^2  10t + 9 = 0
(t9)(t1) = 0
it will reach 45m on the way up at t=1, and on the way back down at t=9.