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March 6, 2015

March 6, 2015

Posted by **Sam** on Sunday, October 28, 2012 at 12:54pm.

- Physics -
**bobpursley**, Sunday, October 28, 2012 at 1:46pmlinear velocity=w*radius

inner velocity=w*(r)

outer velocity=w(r+.340)

So the difference in linear velocities at the track is

outer-inner=w(r+.340-r)=.340 w

Now consider the tires: they have to have the same linear velocity at the pavement. So the difference in tire velocitys is .340w

Inner tire=wit*radtire

outer tire=wot*(radtire)

difference=(wot-wit)radius=w*.340

so the difference in the angular speeds of the two tires is: difference=2Pi*radiustrack*.340/(19.9*radiuswheels)

- Physics -
**Jennifer**, Sunday, October 28, 2012 at 1:53pmw = 2*pi*f

f = 1/19.9

where f is the frequency of the car going around the track, w is the angular speed around the track, pi is 3.14

w = 2*pi/19.9 =0.315

The speed traveled by one tire is

w*r

where r is the radius of the wheel

The speed traveled by the other tire is

w*(r+1.63)

The difference in speeds of the wheels is w*(r+1.63)-w*r = 1.63w = .513 = w(tire)*r(tire)

where w(tire) is the angular speed of the tire, and r(tire) is the radius of the tire

w(tire)*0.340 = 0.513

Solve for w(tire)

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