Sunday

March 29, 2015

March 29, 2015

Posted by **Ifi** on Sunday, October 28, 2012 at 10:07am.

My ans is (-sin x)/ (1+cos x), but at wolfram is

-tan (x/2). I think they simplify it but how did they do it? Sorry for my little knowlegde....

- Math -
**Steve**, Sunday, October 28, 2012 at 12:03pmlook up your half-angle formulas. This is a standard form.

**Answer this Question**

**Related Questions**

calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...

Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...

Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...

Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...

algebra - Can someone please help me do this problem? That would be great! ...

precalculus - For each of the following determine whether or not it is an ...

Math(Please check) - Use the fundamental identities to simplify the expression. ...

Trigonometry - Please review and tell me if i did something wrong. Find the ...

trig 26 - simplify to a constant or trig func. 1. sec Ču-tan Ču/cos Čv+sin Čv ...

Trig. - tan^2BeatacscBeta-tan^2 (simplify) (sin/cos)^2Beta times 1/sin-(sin/cos...