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December 20, 2014

December 20, 2014

Posted by **Ifi** on Sunday, October 28, 2012 at 9:29am.

i need to know the calculation step..thanks for the help....

- Math -
**Steve**, Sunday, October 28, 2012 at 12:02pmWhat? You managed to do e^xlnx, and can't do this one?

y' = ln4 4^(3x^2) (6x)

ooh! Look, that's the same as ln(4^(6x)) 4^(3x^2)

Looks like d/dx a^u = ln(a^u') a^u

but probably better to leave it as lna a^u u'

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