Posted by Ifi on .
Differentiate y=4^(3x^2)..
i need to know the calculation step..thanks for the help....

Math 
Steve,
What? You managed to do e^xlnx, and can't do this one?
y' = ln4 4^(3x^2) (6x)
ooh! Look, that's the same as ln(4^(6x)) 4^(3x^2)
Looks like d/dx a^u = ln(a^u') a^u
but probably better to leave it as lna a^u u'