Saturday
August 23, 2014

Homework Help: physics-mechanics-collisions,momentum, impulse

Posted by HANNE on Sunday, October 28, 2012 at 5:29am.

You are at the controls of a particle accelerator, sending a beam of 2.40×107 protons (mass ) at a gas target of an unknown element. Your detector tells you that some protons bounce straight back after a collision with one of the nuclei of the unknown element. All such protons rebound with a speed of 2.10×107 . Assume that the initial speed of the target nucleus is negligible and the collision is elastic.


1)Find the mass of one nucleus of the unknown element. Express your answer in terms of the proton mass m

2)What is the speed of the unknown nucleus immediately after such a collision?


Momentum:
p is mass of a proton
M is the mass of the nuclei

p*2.4E7=Mv' + p(-2.1E7)
KEnergy:
1/2 p (2.4E7)^2=1/2 M v'^2 + 1/2 p (-2.1E7)^2

Two equations, two unknowns: Let algebra go to work. Solve for v' in the first equation in terms of M
then, put that expression for v' into the second equation. It will work out.


You are at the controls of a particle accelerator, sending a beam of 2.40×107 protons (mass ) at a gas target of an unknown element. Your detector tells you that some protons bounce straight back after a collision with one of the nuclei of the unknown element. All such protons rebound with a speed of 2.10×107 . Assume that the initial speed of the target nucleus is negligible and the collision is elastic.


1)Find the mass of one nucleus of the unknown element. Express your answer in terms of the proton mass m

2)What is the speed of the unknown nucleus immediately after such a collision?

ANSWER I GOT:
•physics-mechanics-collisions,momentum, impulse - bobpursley, Saturday, October 27, 2012 at 6:26am
Momentum:
p is mass of a proton
M is the mass of the nuclei

p*2.4E7=Mv' + p(-2.1E7)
KEnergy:
1/2 p (2.4E7)^2=1/2 M v'^2 + 1/2 p (-2.1E7)^2

Two equations, two unknowns: Let algebra go to work. Solve for v' in the first equation in terms of M
then, put that expression for v' into the second equation. It will work out.

MY CALCULATIONS:
so : v' = 7.52679E-20/M?

and, M= 5.66525677E-39
V' = 7.52679E-20/5.66525677E-39 =
1.328587618E19

is this correct???
please help me. i don't reallly understand this question...

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

physics-mechanics-collisions,momentum, impulse - You are at the controls of a ...
physics-mechanics-collisions,momentum, impulse - You are at the controls of a ...
Physics HELP! - You are at the controls of a particle accelerator, sending a ...
physics - A beam of protons is moving toward a target in a particle accelerator...
physics- MC QUESTION! - Question: A particle is initially traveling to the right...
mc questions - Question # 1-What is the magnitude of the momentum of a particle...
Please help with Physics Quickly - 1. How are impulse and momentum related? (...
physics - when an impulse is given to a particle, momentum is transferred from ...
Physics help? - Nitrogen gas molecules, which have mass 4.65×10−26 kg, are...
Physics - Each of the protons in a particle beam has a kinetic energy of 3.05 10...

Search
Members