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December 20, 2014

December 20, 2014

Posted by **Ifi** on Sunday, October 28, 2012 at 4:52am.

Ans at wolfram is e^(x+e^x). I need the calculation method.

- Math -
**Steve**, Sunday, October 28, 2012 at 6:20amYou know that if y = e^u

y' = e^u u'

here, u=e^x, so

y' = (e^e^x) (e^x)

now just add exponents as usual when multiplying:

y' = e^(e^x+x)

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