Math
posted by Ifi on .
How to differentiate e^e^x?
Ans at wolfram is e^(x+e^x). I need the calculation method.

You know that if y = e^u
y' = e^u u'
here, u=e^x, so
y' = (e^e^x) (e^x)
now just add exponents as usual when multiplying:
y' = e^(e^x+x)