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February 28, 2015

February 28, 2015

Posted by **Ifi** on Sunday, October 28, 2012 at 12:00am.

I think the question is wrong bcus it is impossible to to have 2 unknown to find the relative max or min...right? Sorry if im wrong.

So i change it to f(x)=2x^4-2x^2-9

so for relative max is x = 0 and relative minimum is x= +/- 0.7071. Plz recheck back the answer.

- Math -
**Steve**, Sunday, October 28, 2012 at 12:39amf' = 8x^3 - 4x = 4x(2x^2-1)

you are correct

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