Math
posted by Ifi on .
Let f(t)=2t^42x^29. at what x does f have a local or absolute minimum or maximum?
I think the question is wrong bcus it is impossible to to have 2 unknown to find the relative max or min...right? Sorry if im wrong.
So i change it to f(x)=2x^42x^29
so for relative max is x = 0 and relative minimum is x= +/ 0.7071. Plz recheck back the answer.

f' = 8x^3  4x = 4x(2x^21)
you are correct