Posted by Ifi on Saturday, October 27, 2012 at 9:56pm.
dx/dy cos x sin y + x^5 = 11
i got dx/dy= (-cos x cos y)/ (-sin x sin y +5x^4)
But the wolfram got
(1- cos x cos y)/(5x^4-sin y sin x), where is the 1 come from?
Math - Reiny, Saturday, October 27, 2012 at 11:11pm
so we are differentiating
cosx siny + x^5 = 11 implicitly ?
cosx(cosy) dy/dx + siny(-sinx) + 5x^4 = 0
dy/dx = (sinx siny - 5x^3)/(cosx cosy)
which agrees with my Wolfram result
Math - Reiny, Saturday, October 27, 2012 at 11:17pm
just noticed you wanted dx/dy (strange)
cosx siny + x^5 = 11
cosx(cosy) + siny(-sinx) dx/dy = 5x^4 dx/dy = 0
dx/dy (5x4 - sinxsiny) = - cosxcosy
dx/dy = -cosxcosy/(5x^4 - sinxsiny)
the same as yours.
Math - Ifi, Sunday, October 28, 2012 at 4:53am
At reiny .... Thanks
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