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April 19, 2014

April 19, 2014

Posted by **Jackie** on Saturday, October 27, 2012 at 8:31pm.

- College math -
**Steve**, Sunday, October 28, 2012 at 12:23amAll these complex value problems can be treated just like polynomials, where the reals and imaginaries have to be treated separately

-8i(2i) - 8i(-7)

-16i^2 + 56i

16 + 56i

Don't forget that i^2 = -1

also key: (a+bi)(a-bi) = a^2 - b^2i^2 = a^2+b^2

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