Posted by Jackie on Saturday, October 27, 2012 at 8:31pm.
8i(2i7)

College math  Steve, Sunday, October 28, 2012 at 12:23am
All these complex value problems can be treated just like polynomials, where the reals and imaginaries have to be treated separately
8i(2i)  8i(7)
16i^2 + 56i
16 + 56i
Don't forget that i^2 = 1
also key: (a+bi)(abi) = a^2  b^2i^2 = a^2+b^2