Thursday
March 23, 2017

Post a New Question

Posted by on Saturday, October 27, 2012 at 8:31pm.

-8i(2i-7)

  • College math - , Sunday, October 28, 2012 at 12:23am

    All these complex value problems can be treated just like polynomials, where the reals and imaginaries have to be treated separately

    -8i(2i) - 8i(-7)
    -16i^2 + 56i
    16 + 56i

    Don't forget that i^2 = -1
    also key: (a+bi)(a-bi) = a^2 - b^2i^2 = a^2+b^2

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question