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July 29, 2014

July 29, 2014

Posted by **Anonymous** on Saturday, October 27, 2012 at 6:15pm.

1 yr

- applied algebra -
**Steve**, Saturday, October 27, 2012 at 7:38pmthe fraction left after t years is

(1/2)^(t/5730)

so, you need to solve for t:

.74 = (1/2)^(t/5730)

ln .74 = t/5730 * ln .5

t = 5730 * ln .74/ln .5

t = 2489, or 2500 years

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