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April 20, 2014

April 20, 2014

Posted by **Sammy** on Saturday, October 27, 2012 at 5:50pm.

A) Calculate the maximum acceleration the truck can have before the box slides backwards.

B) The truck just exceeds the maximum acceleration that prevents the box from sliding backwards. Calculate the acceleration of the box.

- Physics -
**Henry**, Sunday, October 28, 2012 at 8:42pmWb = m*g = 35kg * 9.8N/kg = 343 N. = Wt.

of box.

Fb = 343N @ 0o.

Fp=343*sin(0) = 0.=Force parallel to bed

Fv = 343*cos(0) = 343 N. = Force perpendicular to bed.

Fs = u*Fv = 0.3*343 = 102.9 N. = Force of static friction.

A. Fn = Fp - Fs = m*a.

0 - 102.9 = 35*a

qa = -2.94 m/s^2.

B. Fk = u*Fv = 0.1*343 = 34.3 N.

Fp - Fk = m*a.

0-34.3 = 35*a

a = -0.98 m/s^2.

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