Posted by Anonymous on Saturday, October 27, 2012 at 3:13pm.
w = alpha t = .65*3 = 1.95 radians/second
friction force = .42 * m * g = 4.12 m
Ac = w^2 R
centripetal force required = m w^2 R
m w^2 R = 4.12 m if slip is outward
Note I am ignoring tangential slip due acceleration, check later
w^2 = 4.12/R = 4.12/.18 = 22.9
w = 4.78 rad/s at spin out
4.78 = alpha t
t = 4.78/.65 = 7.36 seconds
go back and check tangential slip to make sure it is negligible
tangential acceleration = alpha R
= .65 * .18 = .117 meters/s^2
that is tiny compared to g so forget it
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