Posted by wan on .
2poles are placed vertically in a pool.one third of the longer pole and two fifths of the shorter pole is under water.if the difference in leng 42 cm,how deep is the pool?th

math 
bobpursley,
LS=42
now water height is the same, so
1/3 L = 2/5 S
LS=42
5L6S=0
solve.