Homework Help: math

Posted by wan on Saturday, October 27, 2012 at 4:18am.

2poles are placed vertically in a pool.one third of the longer pole and two fifths of the shorter pole is under water.if the difference in leng 42 cm,how deep is the pool?th

math - bobpursley, Saturday, October 27, 2012 at 6:36am
L-S=42
now water height is the same, so
1/3 L = 2/5 S

L-S=42
5L-6S=0

solve.

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