(index of 3)square root of 3r-6(equals 3)

what a strange notation. I'd have said

cuberoot(3r-6) = 3
so,
3r-6 = 3^3 = 27
3r = 33
r = 11

To find the value of "r" that satisfies the equation (index of 3)square root of 3r-6 = 3, we can use the following steps:

Step 1: Start with the equation: (index of 3)square root of 3r-6 = 3.

Step 2: Raise both sides of the equation to the power of 3 to remove the index 3 on the left side: [(index of 3)square root of 3r-6]^3 = 3^3.

Step 3: Simplify the left side of the equation: 3r - 6 = 27.

Step 4: Add 6 to both sides of the equation: 3r = 33.

Step 5: Divide both sides of the equation by 3 to solve for "r": r = 11.

Therefore, the value of "r" that satisfies the equation is 11.

To find the value of r in the equation √(3r-6) = 3, we can follow these steps:

Step 1: Square both sides of the equation to eliminate the square root:

(√(3r-6))^2 = 3^2

This simplifies to:

3r-6 = 9

Step 2: Add 6 to both sides of the equation to isolate the term with 'r':

3r - 6 + 6 = 9 + 6

This simplifies to:

3r = 15

Step 3: Divide both sides of the equation by 3 to solve for 'r':

3r / 3 = 15 / 3

This simplifies to:

r = 5

So, the value of r that satisfies the equation √(3r-6) = 3 is r = 5.