a. masswater=difference wet-dry mass
c. moles cobaltII sulfite=dry mass/molmassCobaltII sulfite
d. ratio water=moleswater/molessulfite
formula CoSO3.nH2O where n is found in step d.
mass hydrated salt = 43.0
mass anhydrous salt = 26.1
mass H2O lost = 43.0-26.1 = 16.9g
mols H2O = 16.9/molar mass H2O = ?
mols CoSO3 = 26.1/molar mass CoSO3=?.
Find the ratio of the two with CoSO3 being 1.00. The easy way to do that is to divide the mols of BOTH by mols CoSO3. That way CoSO3 = 1.000000000, divide the H2O by the same number and round to a whole number. Then the formula for the hydrate will be CoSO3.xH2O where x is the whole number.
Post your work if you get stuck and I can help you through it. Actually this is pretty simple.
Ok. Please. Check. Thank you both so much.
Mass of water:
43.0-26.1=16.9 g H2O
Moles of water:
(16.9 g H2O)(1 mol H2O/18.0 g H2O)= 0.939 mol H2O
Moles of cobalt (II) sulfite:
CoSO3= 58.9332+32.066+3(15.9994)=138.9974 g/mol
(26.1 g CuSO3)(1 mol CuSO4/138.9974 g CuSO3)= 0.188 mol CuSO3
Mole ratio of water to cobalt (II) sulfite and correct formula:
0.188 mol CuSO3/0.188 mol CuSO3= 1.000 mol CuSO3
0.939 mol H20/0.188= 4.99 (round up)= 5 H2O
I didn't check the math step by step but the formula is correct at CoSO3.5H2O.
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