college algebra
posted by zachary on .
write the equation of the circle in standard form find the center radius, intercept and graph circle
x^2 +y^2+8x+2y+8=0

rearrange things a bit to get
x^2+8x + y^2+2y = 8
Now complete the squares:
x^2+8x+16 + y^2+2y+1 = 8 + 16 + 1
(x+4)^2 + (y+1)^2 = 9
center at (4,1)
when y=0,
(x+4)^2 + 1 = 9
(x+4) = ±√8
x = 4 ± √8
similarly for y when x=0