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March 30, 2017

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the perimeter of a rectangle is 160m and its area is 1200m^2 find its dimensions

  • math - ,

    I'll get you started.

    √ 1200 = 34.64

  • math - ,

    then what i seriously have no clue what im doing

  • math - ,

    With a little trial and error, I found that the dimensions must be 20 by 60

  • math - ,

    2w + 2l = 160
    w+l = 80
    l= 80-w

    wl = 1200
    w(80-w) = 1200
    80w - w^2 - 1200=0
    w^2 - 80w + 1200 = 0
    (w-20)(w - 60) = 0
    w = 20 or w = 60

    if w = 20, then l = 80-20 = 60
    and if w - 60 , then l = 80-60 = 20

    So the rectangle is 20 by 60 as Ms Sue found by trial-and-error

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