Posted by **nina** on Thursday, October 25, 2012 at 10:49pm.

a farmer has cows and chickens. he has a total of 20 heads and 64 legs. How much of each animal does he have?

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**Prasad**, Thursday, October 25, 2012 at 11:42pm
Let X be the no of cows and Y be number of chickens

No of Heads = 20

x+y = 20

No. of legs = 64

4x + 2 y = 64

Solve the system of equation x+y = 20

4x + 2y = 64

You will get x = 12, y = 8

No. of cows = 12

No. of chickens = 8

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**L**, Friday, July 22, 2016 at 1:37am
Power

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**rita**, Thursday, October 13, 2016 at 9:21pm
a farmer kept track of his cows and hens by counting the legs and the heads.if he counted 78 legs anf 35 heads,hw many cows did he have?

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