Homework Help: physics

Posted by ashley on Thursday, October 25, 2012 at 10:29pm.

A 4.170 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is μs = 0.505 and the coefficient of kinetic friction is μk = 0.255. At time t = 0, a force F = 12.7 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times:
t=0 and t>0

physics - Habeeb, Thursday, October 25, 2012 at 10:41pm
Friction = uN

N=mg so

F=umg

F at t(0) = (.505)(4.17 kg)(9.8 m/s^2)

F at t>0 = (.255)(4.17 kg)(9.8 m/s^2)

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