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Only two forces act on an object (mass = 4.00 kg), as in the drawing. Find the magnitude and direction (relative to the x axis) of the acceleration of the object.

Angle=tan-1(60/40)= 56.3° (How did you get 56.3°)
a= F/m=72.11/4=18(m/s/s)

The correct answer is 18.0 m/s2, 56.3° above the +x axis. I was wondering how did you get 56.3°? Please show your work

  • physics - ,

    α=arctan(Fy/Fx)=arctan(60/40)=arctan 1.5=56.3°

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