Posted by Anonymous on Thursday, October 25, 2012 at 3:15pm.
Only two forces act on an object (mass = 4.00 kg), as in the drawing. Find the magnitude and direction (relative to the x axis) of the acceleration of the object.
Ftotal=Sqrt(60^2+40^2)=72.11(N)
Angle=tan1(60/40)= 56.3° (How did you get 56.3°)
a= F/m=72.11/4=18(m/s/s)
The correct answer is 18.0 m/s2, 56.3° above the +x axis. I was wondering how did you get 56.3°? Please show your work

physics  Elena, Friday, October 26, 2012 at 1:36am
α=arctan(Fy/Fx)=arctan(60/40)=arctan 1.5=56.3°