Posted by D on .
The drawing shows a circus clown who weighs 710 N. The coefficient of static friction between the clown's feet and the ground is 0.49. He pulls vertically downward on a rope that passes around three pulleys and is tied around his feet. What is the minimum pulling force that the clown must exert to yank his feet out from under himself?
F(fr)= μN=μ(mg- T) = μmg-μT =T
T= μmg/(1+μ)=0.49•710/1.49=233.5 Newtons