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October 1, 2014

October 1, 2014

Posted by **Alphonse** on Thursday, October 25, 2012 at 1:31pm.

- Physics -
**Elena**, Thursday, October 25, 2012 at 2:54pmInitial heights of the blocks: m1 -> H; m2 -> h

Initial energy of the “two blocks” system is

E1 = m1•g•H+m2•g•h

When the blocks covered s=0.9 m the energy of ”two blocks+spring” system is

E2= m1•g(H-s•sinα) +m1•v²/2 {m2•g(h+s) +m2•v²/2 +ks²/2.

From the law of conservation of energy

E1-E2 =W(fr)

W(fr) =μ•m1•g•cosα•s.

m1•g•H+m2•g•h- m1•g(H-s•sinα) - m1•v²/2 {m2•g(h+s) - m2•v²/2 -ks²/2 = μ•m1•g•cosα•s.

v=sqrt[{ 2gs(m1•sinα-m2)-kx²-2•μ•m1•g•cosα•s}/(m1+m2)]

I got v= 2.26 m/s. Check my calculations.

- Physics -
**AH**, Thursday, October 25, 2012 at 9:27pmSorry, how did you get the angle and what is x?

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