An object in equilibrium has three forces exerted on it. A 36 N force acts at 90° from the x axis and a 42 N force acts at 60°. What are the magnitude and direction of the third force?
Physics URGENT! PLEASE - Elena, Thursday, October 25, 2012 at 1:19pm
ΣF(x) =F1(x) +F2(x) +F3(x) =0
F3(x) = -42•cos60°= -21 N
ΣF(y) =F1(y) +F2(y) +F3(y) =0
F3(y) =-36 -42•sin60°= -72.4 N