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Posted by on Thursday, October 25, 2012 at 12:13pm.

1.given the function y=x^2-4x+5,find the following:
a.vertex
b.maximum or minimum
c.axis of symmetry
d.y-intercept
e.x-intercept(zeros)
f.graph

  • geometery - , Thursday, October 25, 2012 at 2:19pm

    complete the square ....

    y = x^2 - 4x + 4 - 4 + 5
    = (x-2)^2 + 1

    vertex is (2,1)
    opens up, so minimum
    axis of symmetry: x = 2
    y-intercepts: let x = 0, y = 5
    x-intercepts:
    let y = 0
    x^2 - 4x+ 5 = 0
    (x-5)(x+1) = 0
    x = 5, x = -1 , notice the x of the vertex is midway between these.

    graph: you do it.

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