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A 0.5 kg block is sliding along a table top with an initial velocity of 0.2 m/s. It slides to rest in a distance of 70 cm. Find the frictional force that is slowing its motion.

  • physics -

    KE = m•v²/2
    W(fr) =F(fr) •s
    m•v²/2 =F(fr) •s
    F(fr)= m•v²/2•s

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