posted by Bill on .
What volume of the solution in 5a would be necessary to react completely with 23.00mL of 0.549M NH3 according to the equation: NiSO4+6NH3 -> [Ni(NH3)6]SO4
The molarity of ta is 1.667 x 10^-4M
Is ta a typo for 5a? Is tghe solution is 5a(ta) NiSO4?
mols NH3 = M x L = ?
mols NiSO4 = (1/6) x mols NH3
M NiSO4 = mols NiSO4/L NiSO4. You know M and mols, solve for L.