Posted by Steeve on .
The coefficient of kinetic friction for a 34.3 kg bobsleigh on a track is 0.150. What external force is required to push it down a 5.60° incline and achieve a speed of 60.12 km/h at the end of 75.2m ?
PE=KE + W(fr)
mgh =mv²/2 + F(fr)•s
m•g•s•sinα =mv²/2 +μ•m•g•cosα•s
Solve for μ