Homework Help: Physics

Posted by Brenda on Wednesday, October 24, 2012 at 5:45pm.

I found the average acceleration of earths orbit around the sun over a period of 5 days by calculating delta theta and dividing by radius and 1/T.

I got the right answer but as I am studying for my test, I am seeing the units do not work...does this make sense? Can someone derive that equation for me?

So here is what I have:

theta = 0.086 rads
time = 432,000 seconds (5 days)
radius = 6.371x10^6

(0.086 x 432,000)/6.371x10^6 = 0.006

Physics - Elena, Thursday, October 25, 2012 at 1:02pm
You accidentally got the right answer.
Correect solution is following:
The Earth makes one revolution (2π) during 1 year => the angular displacement for 5 days is
θ= 2π•5/365 = 0.086 rad.
The angular velocity of the Earth is
ω= θ/t = 0.086/5•24•3600 =2•10⁻⁷ rad/s
If R = 1.496•10¹¹ m, the centripetal acceleration of the Earth is
a=ω²•R =(2•10⁻⁷)²•1.496•10¹¹ = 0.006 m/s²

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