Saturday

March 28, 2015

March 28, 2015

Posted by **Bill** on Wednesday, October 24, 2012 at 1:09pm.

For the second derivative I got f(x)=6x-16 and then got x=16/6 when set to zero.

- Calculus -
**Damon**, Wednesday, October 24, 2012 at 1:35pm3 x^2 -16 x + 5 = 0

first derivative

at x = {16 +/-sqrt(256-60)]/6

or [16+/-14]/6 = 5 or 0.3333

second derivative

6 x - 16

is that + or - at the two points where the slope is zero?

at x = .333

2 - 16 is negative so maximum there

at x = 5

6x - 16 = 30-16 is positive so minimum there

**Answer this Question**

**Related Questions**

calc. - I'm having a lot of trouble with this problem: Sketch the graph and show...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...

Calculus- answer check - A brand new stock is also called an initial public ...

calculus - a function has a local maximum at x=-2 and x=6 and a local minimum at...

calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...

Please check my Calculus - 1. Find all points of inflection: f(x)=1/12x^4-2x^2+...

Calculus - f(x)= x/(1+x)^2 a) find the intervals on which f is increasing or ...

Calculus A - Find all relative extrema and points of inflection for the ...

Calculus - Determine whether or not each of the following functions is ...