Posted by Bill on Wednesday, October 24, 2012 at 1:09pm.
3 x^2 -16 x + 5 = 0
first derivative
at x = {16 +/-sqrt(256-60)]/6
or [16+/-14]/6 = 5 or 0.3333
second derivative
6 x - 16
is that + or - at the two points where the slope is zero?
at x = .333
2 - 16 is negative so maximum there
at x = 5
6x - 16 = 30-16 is positive so minimum there
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