A computer is reading data from a rotating CD-ROM. At a point that is 0.0382 m from the center of the disk, the centripetal acceleration is 118 m/s2. What is the centripetal acceleration at a point that is 0.0791 m from the center of the disc?
physics - Jennifer, Wednesday, October 24, 2012 at 10:22am
the centripetal acceleration is omega^2*r
where omega is the angular velocity, and r is the radius at that point
118 m/s^2 = omega^2*0.382
solve for omega, then find a :
a = omega^2 * 0.0791