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24cm^3 of a mixture of methane and ethane were exploded with 90cm^3 of oxygen. After cooling to RTP the volume of gases was noted and it decreased by 32cm^3 when treated with KOH. Calculate the composition of the mixture.


    CH4 + 2O2 ==> CO2 + 2H2O
    2C2H6 + 7O2 ==> 4CO2 + 6H2O

    I would look at this. Since we have all gases we need not convert to mols but we can use volume directly.

    Let x = volume CH4
    and y = volume C2H6
    x + y = 24 cc which is equation 1.
    x cc of CH4 will produce x cc of CO2.
    y cc of C2H6 will produce 4y/2 = 2y CO2 so equation 2 is
    x + 2y = 32. Solve those two equations simultaneously for cc x and cc y.


    Thank you DrBobb22

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