A rocket booster fires in space with a force of 500N and moves the 10kg satellite from rest to motion in 2.1 seconds. Find the acceleration? What is the final speed of the satellite?
F= 500N , m= 10kg , t= 2.1s , a=? , v(f)=?
F= (m)(a) therefore a= F/m
so a= 500/10= 50ms
and v= u(i) + (a)(t)
so v(f)= 0 + (50)(2.1)= 105ms
note=== v(f) is final velocity and v(i) is initial velocity.
To find the acceleration, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a):
F = m * a
In this case, the force (F) is given as 500N and the mass (m) of the satellite is 10kg.
500N = 10kg * a
Now, we can solve for the acceleration (a). Dividing both sides of the equation by 10kg:
a = 500N / 10kg
a = 50 m/s^2
So, the acceleration of the satellite is 50 m/s^2.
To find the final speed of the satellite, we can use the formula:
v = u + at
where v is the final velocity, u is the initial velocity (which is 0 since the satellite is at rest), a is the acceleration, and t is the time taken.
Plugging the values into the formula:
v = 0 + 50 m/s^2 * 2.1 s
v = 105 m/s
Therefore, the final speed of the satellite is 105 m/s.