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March 25, 2017

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(cosxcotx/secx+tanx)+(sinx/secx-tanx)

  • Precalculus - ,

    making everything sin and cos, we have

    (cos^2/sin)/(1/cos + sin/cos) + sin/(1/cos - sin/cos)
    cos^2/sin * cos/(1+sin) + sin*cos/(1-sin)
    cos^3/(sin(1+sin)) + sin*cos/(1-sin)
    (cos^3(1-sin) + sin^2*cos(1+sin))/(sin(1-sin^2))
    (cos^3 - sin*cos^3 + cos*sin^2 + sin^3)/(sin*cos^2)
    (cos^2 - sin*cos^2 + sin^2)/(sin*cos)
    cot - cos + tan

    whew - better double-check

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