Posted by **Milak** on Tuesday, October 23, 2012 at 8:55pm.

(cosxcotx/secx+tanx)+(sinx/secx-tanx)

- Precalculus -
**Steve**, Tuesday, October 23, 2012 at 9:14pm
making everything sin and cos, we have

(cos^2/sin)/(1/cos + sin/cos) + sin/(1/cos - sin/cos)

cos^2/sin * cos/(1+sin) + sin*cos/(1-sin)

cos^3/(sin(1+sin)) + sin*cos/(1-sin)

(cos^3(1-sin) + sin^2*cos(1+sin))/(sin(1-sin^2))

(cos^3 - sin*cos^3 + cos*sin^2 + sin^3)/(sin*cos^2)

(cos^2 - sin*cos^2 + sin^2)/(sin*cos)

cot - cos + tan

whew - better double-check

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