Posted by asdf on Tuesday, October 23, 2012 at 8:11pm.
if the man starts at t=0, his position at time t is (0,4t)
The woman is at (500+5(t-5),0)
the distance d is
d^2 = (500+5(t-5))^2 + (4t)^2 = 41t^2 + 4750t + 225625
at t=15,
d^2 = 306100, so d=553.26
2d dd/dt = 82t + 4750
1106.52 dd/dt = 5980
dd/dt = 5.4 ft/s
makes sense, since the 500' lead makes most of the distance due to the woman's motion, at 5 ft/s
Rats. I thought she was walking east.
she is at (500,-5(t-5))
d^2 = 500^2 + (4t+5(t-5))^2 = 81t^2 - 450t + 250625
at t=15, d = 512
2d dd/dt = 162t - 450
1024 dd/dt = 1980
dd/dt = 1.93 ft/s
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