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November 26, 2014

November 26, 2014

Posted by **asdf** on Tuesday, October 23, 2012 at 8:11pm.

I'm confused about the diagram and what to do with time

- calculus -
**Steve**, Tuesday, October 23, 2012 at 8:40pmif the man starts at t=0, his position at time t is (0,4t)

The woman is at (500+5(t-5),0)

the distance d is

d^2 = (500+5(t-5))^2 + (4t)^2 = 41t^2 + 4750t + 225625

at t=15,

d^2 = 306100, so d=553.26

2d dd/dt = 82t + 4750

1106.52 dd/dt = 5980

dd/dt = 5.4 ft/s

makes sense, since the 500' lead makes most of the distance due to the woman's motion, at 5 ft/s

- calculus - oops -
**Steve**, Tuesday, October 23, 2012 at 8:47pmRats. I thought she was walking east.

she is at (500,-5(t-5))

d^2 = 500^2 + (4t+5(t-5))^2 = 81t^2 - 450t + 250625

at t=15, d = 512

2d dd/dt = 162t - 450

1024 dd/dt = 1980

dd/dt = 1.93 ft/s

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