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chemistry

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how many milliliters of 0.250 M KMnO4 are needed to react with 3.55 grams of iron(II)sulfate, FeSO4? the reaction is as follows:
10FeSO4(aq)+2KMnO4(aq)+8H2SO4(aq)¨
5Fe2(SO4)3(aq)+2MnSO4(aq)+K2SO4(aq)+8H2O(l)

  • chemistry - ,

    mols FeSO4 = grams/molar mass = ?
    Use the coefficients in the balanced equation to convert mols FeSO4 to mols KMnO4.
    M KMnO4 = mols KMnO4/L KMnO4. You know M and mols, solve for L and convert to mL.

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