posted by robert on .
how many milliliters of 0.250 M KMnO4 are needed to react with 3.55 grams of iron(II)sulfate, FeSO4? the reaction is as follows:
mols FeSO4 = grams/molar mass = ?
Use the coefficients in the balanced equation to convert mols FeSO4 to mols KMnO4.
M KMnO4 = mols KMnO4/L KMnO4. You know M and mols, solve for L and convert to mL.