Physics
posted by Laurie on .
If a rod is moving at a velocity equal to 1/2 the speed of light parallel to its length, what will a stationary observer observe about its length?
The length of the rod will become exactly half of its original value.
The length of the rod remains the same.
The length of the rod will decrease.
The length of the rod will increase.
I would think D

L=L₀•sqrt{1(v/c)²}=0.866L₀
The length of the rod will decrease.