posted by Kaitlin on .
For the following reaction, 3.93 grams of carbon tetrachloride are mixed with excess methane (CH4). The reaction yields 4.10 grams of dichloromethane (CH2Cl2).
methane (CH4) (g) + carbon tetrachloride (g) dichloromethane (CH2Cl2) (g)
What is the theoretical yield of dichloromethane (CH2Cl2) ? grams
What is the percent yield for this reaction ?
mols CCl4 = grams/molar mass = ?
Convert mols CCl4 to mols of the product using the coefficients in the balanced equation. .
Convert mols of the product to grams. g = mols x molar mass. This is the theoretical yield (TY).
The actual yield (AY) = 4.10 g.
% product = (AY/TY)*100 = ?