Posted by **member of physics** on Tuesday, October 23, 2012 at 12:05am.

A single conservative force = (6.0x - 12) N where x is in meters, acts on a particle moving along an x axis. The potential energy U associated with this force is assigned a value of 23 J at x = 0.

(a) Write an expression for U as a function of x, with U in joules and x in meters.

U(x) =

(b) What is the maximum positive potential energy?

J

(c) At what negative value of x is the potential energy equal to zero?

m

(d) At what positive value of x is the potential energy equal to zero?

m

- Physics Please help !! -
**Elena**, Tuesday, October 23, 2012 at 10:00am
ΔU = U(x) - U(0) = ∫(6x - 12)dx

Therefore, with U(0) = 23 J, we obtain by integrating

U = 23 + 12x - 3x ²

F = 0 when 6x - 12 = 0

Thus x = 2 m

Substituting into U = 23 + 12x² - 3x ,

U = 35 J

Using the quadratic equation find the negative and positive values of x for which U = 0

3x ² - 12x-23 =0

x=(12±sqrt(144+4•3•23)}/2•6

x = -1.42 m

x = 5.42 m

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