Posted by Alex on Monday, October 22, 2012 at 8:33pm.
Find the derivative of y with respect to x. y=(x^6/6)(lnx)-(x^6/36)
So far this is what I've gotten:
What do I do now?
- Calculus 1 - Steve, Tuesday, October 23, 2012 at 12:03am
You forgot various parts.
If y = uv, y' = u'v + uv'
If y = u^n, y' = nu^(n-1) u'
y' = [1/6 * 6x^5 * lnx] + [1/6 x^6 * 1/x] - 1/36 * 6x^5
or, you can factor stuff out first:
y = 1/6 x^6 (lnx - 1/6)
y' = [1/6 * 6x^5](lnx - 1/6) + 1/6 x^6 * (1/x)
Either way you can massage things till you get
Answer this Question
- calculus - sorry to ask a second question so soon, but i'm just not getting this...
- L'Hopital's rule - Find lim x->1+ of [(1/(x-1))-(1/lnx)]. Here is my work...
- calculus - (a) find the intervals on which f is incrs or decrs. (b) find the ...
- Calculus - Find the derivative of y with respect to x. y= [(x^5)/5]lnx-[(x^5)/25...
- Calculus - Find the derivatives, dy/dx for the following functions. a. x^2y^4 = ...
- calc - integral of 1 to e^4 dx/x(1+lnx) 1+lnx = a => dx/x = da dx/ x(1+lnx...
- Math - Find the coordinates of the turning point and determine wether it is ...
- College Calc - Problem: y=sqrtx ^1/x. Find DY/DX. ln(f(x))=lnx^1/2x or lnx to ...
- math - how would you solve for y in this problem: ln(y-1)-ln2 = x +lnx ln(y-1)-...
- calculus - find dy/dx 1. y=(lnx)^3 2. y=x^4lnx 3. y=sin^3(lnx)