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April 18, 2014

Homework Help: Chemistry

Posted by Josh on Monday, October 22, 2012 at 6:40pm.

I titrated 0.25 grams of soda ash with 43.7 mL of HCl (0.115M) and 25 mL of H2O. I am getting over 100% sodium carbonate in my answer here are my steps that I took to get the answer can somebody help me see what I did wrong?

mols HCl=(0.115M)x (0.0437L)=0.005 mol HCl

1/2 x (0.005)= 0.0025mol Na2CO3

0.0025mol x 105.99g= 0.42g Na2CO3

0.42g/0.25g x 100%= 168%

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