Posted by **sarah** on Monday, October 22, 2012 at 6:16pm.

A right triangle is formed in the first quadrant by the x- and y-axes and a line through the point (2,3). Draw a figure that illustrates the problem.

What is the area of the triangle A as a function of the x-intercept of the line?

- math -
**Steve**, Monday, October 22, 2012 at 6:36pm
If the x-intercept is at x=h, then we must have h>2 to fit the conditions.

Now we have two points, and our line is

(y-3)/(x-2) = (0-3)/(h-2)

y = 3/(2-h) * (x-2)

at x=0, y = 6/(h-2)

the area is thus 1/2 xy = 1/2 h(6/(h-2)) = 3h/(h-2)

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